e.g: Enthalpy change for the burning of methane
Bond energies should be given as
C– H = 99 KJ/mol
O=O = 119 KJ/mol
C=O = 192 KJ/mol
O– H = 111 KJ/mol
By looking at the structures of the molecules involving in the reaction for breaking bonds
- 4 C-H bonds
- 2 O=O bonds has to be broken
Total energy for breaking the bonds
99*4 +119*2 =
396+238=
634 KJ/mol
For making bonds from the reaction
- 2 C=O bonds
- 4 O– H bonds has to be made
192* 2+ 111*4=
384 +444=
828 KJ/mol
Enthalpy change= energy needed to break the bonds- energy taken to make the bonds
ΔH° =634-828
= - 194 KJ/mol
If the enthalpy change come as a negative value it is an exothermic reaction. If it was positive it is endothermic. According to this example this reaction is exothermic.
1:36 AM
bond energies
burning of methane
calculating enthalpy change
enthalpy change
exothermic reaction example